Question

Please help me with this question.... ASAP
Part (a) only ​

Answer 1

Answer:

$\huge\underline\pink {Answer }$

Given:-

Side 1 = 3m

Side 2 = 8m

The given triangle is right angled

To Find:-

Side x

Proof:-

The triangle is right angled.

According to Pythogoras theorem - Square of hypotenuse is equal to the sum of squares of another two sides.

Therefore -

${8}^{2} = {3}^{2} + {x}^{2}$

$64 = 9 + {x}^{2}$

${x}^{2} = 64 - 9$

$x = \sqrt{64 - 9}$

$x = \sqrt{55}$

$\large\fbox\fcolorbox {red}{green} {x=7.14}$

Answer 2

Answer:

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Step-by-step explanation:

Given:-

Side 1 = 3m

Side 2 = 8m

The given triangle is right angled

To Find:-

Side x

Proof:-

The triangle is right angled

According to Pythogoras theorem - Square of hypotenuse is equal to the sum of squares of another two sides

Therefore :-

8² = 3²+x²

64 = 9 + x²

x² = 64 - 9

x = √ 64 -9

x = √ 55

x = 7.14

$\huge\colorbox{pink}{§hizűka࿐ ❤}$