Question

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Answer 1

Answer:

a) total current- 0.11... ampere

b) 2 resistors in parallel and the rest 2 in parallel

Explanation:

a) as given in the figure,

15Ω and 15Ω are connected in series and 30Ω and 30Ω are connected in parallel

R=R1+R2(Series)

=15Ω+15Ω=30Ω

1/R=1/R1+1/R2(Parallel)

=1/30Ω+1/30Ω= 1/15Ω= 15Ω

Total resistance in circuit=15Ω+30Ω= 45Ω

According to ohm's law, R=V/I

=45Ω=3V/I

1=1/9=0.11

b) connect two resistors in parallel so that total resistance is 4Ω and the other 2 again in parallel so it is 4Ω.

So effective resistance is =4Ω+4Ω=8Ω

Answer 2

Answer 1

See the attachment

Here I have simplified the circuit and also find the equivalent resistance in circuit which is 10Ω.

Now apply ohms law to find current,I.

V=IR

3v=I(10Ω)

3/10A=I

0.3 A=I

Hence the current in circuit is 0.3 Ampere.

Answer 2

We will connect the given resistance in order given in 2nd attachment.

It is kind of logical Question where we have to use trial method to get the required equivalent resistance.

Here in attachment we can see that R1 and R2 are in series connect.

SOLUTION:

Let's find equivalent resistance for R1 and R2.

Re=R1+R2

Re=8Ω+8Ω

Re=16Ω

R3 and R4 are also in series.

So their equivalent resistance Re1 is:-

R3+R4

=8+8Ω

=16Ω

Also Re1 and Re are in Parellel connection

So their equivalent resistance will be

1/Rq=1/16+1/16

1/Rq=2/16

1/Rq=1/8

Rq=8Ω

This is equal to the required equivalent resistance.