please help prove the following
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(sin A + cos A)^2+(sin A - cos A)^2=2
ON LHS
(sin A + cos A)^2+(sin A - cos A)^2
=sin^2 A+2.sin A. cos A +cos^2 A+sin^2 A-2.sin A.cos A+cos^2 A
=2 sin^2 A + 2 cos ^2 A
=2 (sin^2 A+cos^2 A)
=2×1
=2
therefore LHS=RHS
(sin A+cos A)^2+(sin A- cos A)^2=2
PROVED
ON LHS
(sin A + cos A)^2+(sin A - cos A)^2
=sin^2 A+2.sin A. cos A +cos^2 A+sin^2 A-2.sin A.cos A+cos^2 A
=2 sin^2 A + 2 cos ^2 A
=2 (sin^2 A+cos^2 A)
=2×1
=2
therefore LHS=RHS
(sin A+cos A)^2+(sin A- cos A)^2=2
PROVED
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here is the answer.....
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