Question

please help this by rationalising denominator

Answer 1

$Given:\frac{5+2\sqrt{3}}{7+4\sqrt{3}}$

$=>\frac{5+2\sqrt{3}}{7+4\sqrt{3}}*\frac{7-4\sqrt{3}}{7-4\sqrt{3}} = a+b\sqrt{3}$

$=>\frac{(5+2\sqrt{3})(7-4\sqrt{3})}{(7+4\sqrt{3})(7-4\sqrt{3}} =a+b\sqrt{3}$

$=>\frac{35-20\sqrt{3}+14\sqrt{3}-24}{49-48}=a+b\sqrt{3}$

$=>\frac{35-6\sqrt{3}-24}{1} = a + b\sqrt{3}$

$=> 11 - 6\sqrt{3} = a + b \sqrt{3}$

Therefore,

The value of a = 11.

The value of b = -6.

Hope this helps!

Answer 2

Answer:

a = 11, b = -6

Step-by-step explanation:

The answer is explained below