Question

please if u can answer this question it will be a big help

Answer 1

let the no of passenger having 3 ruppes ticket = x
And the passenger whom have 10 ruppee ticket = y

Case 1 :

x + y = 40
x = 40 - y ___________1

Case 2:
3x + 10 y = 295 ________ 2

Now put the value of x in equation 2

3 ( 40 -y ) + 10y = 295

120 - 3y + 10y = 295

120 + 7y = 295

7y = 295 - 120

7y = 175

y = 175 / 7

y = 25

Now put the value of y in equation 1 .

x = 40 - 25

x = 15

The passenger having 3 rupees ticket are
15 and passengers having 10 rupees ticket are 25 .

May it helps you ^ _ ^

Answer 2

24.)let the no.of passengers having Rs.3 tickets be x
           the no.of passengers having Rs.10 tickets be y
According to the question,
Total passengers=40
⇒x+y=40
⇒y=40-x   
 Total Collection=Rs.295
⇒3x+10y=295
subsstitute y=40-x in 3x+10y=295
⇒3x+10(40-x)=295
⇒3x+400-10x=295
⇒400-7x=295
⇒7x=400-295
⇒7x=105
⇒x=15

15 passengers have Rs.3 tickets.

25.) AB=210 km
let speed of 1st car=x km/h
speed of 2nd car=x-8 km/h
After 3 hours,
distance travelled by 1st car=3x km
distance travelled by 2nd car=3(x-8)
                                              =3x-24 km
According to question,
   3x+3x-24=210 km
⇒6x-24=210 km
⇒6x=234
⇒x=234/6
⇒x=39
Speed of one car=39 km/h
Speed of other car=31 km/h

Hope this helps u :-)