please keep fastly.I will mark you as ambitious
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0
_________________
solution are (x,y)=(0,0)
_________________
second,
now dividing both equation by xy
and multiply than adding we get,
the above mention result show in image
now supposing 1/x=a and 1/y=b
than by elimination method we will get another solution
a+b=5
2a+5b=13
b=1
1/y=1
y=1
so,
x=1/4
solution are (x,y)=(1/4,1)
Plz Plz make my answer as brainliest answer.
solution are (x,y)=(0,0)
_________________
second,
now dividing both equation by xy
and multiply than adding we get,
the above mention result show in image
now supposing 1/x=a and 1/y=b
than by elimination method we will get another solution
a+b=5
2a+5b=13
b=1
1/y=1
y=1
so,
x=1/4
solution are (x,y)=(1/4,1)
Plz Plz make my answer as brainliest answer.
DJpriyamehra:
i want reducing method
Answered by
3
Answer:
x = 1/2, y =1/3
Step-by-step explanation:
Given Equations are:
3x + 2y = 13xy
4x - 5y = 2xy
Divide both the equations by xy, we get
(3/y) + (2/x) = 13
(4/y) - (5/x) = 2
Let (1/y) = p, (1/x) = q the the equation becomes,
3p + 2q = 13 --- (i)
4p - 5q = 2 --- (ii)
On solving (i) * 4 & (ii) * 3, we get
12p + 8q = 52
12p - 15q = 6
-------------------
23q = 46
q = 46/23
q = 2.
Substitute q = 2, we get
12p + 8q = 52
12p + 8(2) = 52
12p = 52 - 16
12p = 36
p = 3.
Now,
(i) q = 2
So, x = 1/2.
(ii) p = 3.
So, y = 1/3.
Therefore, x = 1/2, y = 1/3.
Hope it helps!
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