Question

please let me know the answer ​

Answer 1

Answer:

6 times is redius of vire

Step-by-step explanation:

it is your anser

Answer 2

$\bold{\LARGE{\underline{\underline{Question:–}}}}$

The radius of a wire is decreased to one-third, if volumes remain same, the length of wire becomes

$\bold{\LARGE{\underline{\underline{Answer:–}}}}$

(d) 9 times

______________________

$\bold{\LARGE{\underline{\underline{Explanation:–}}}}$

$Let\: r_1 \: and\: r_2 be \:radius$

In first condition :

$π \:r^2_1\:h = V$

So, r² = $\frac{r_1}{2}$

Now,

${π}\:r^2_1\:h_1\:=\:{π}\:r^2_2\:h_2$

$r^2_1\:h_1\:\:=\:\:( \frac{r_1}{3})²\:h_2$

${r^2_1}\:h_1\:\:=\:\:\frac{r^2_1}{9}\:\:h_2$

$Therefore,\: h_1\:\:=\:\:\frac{h_2}{9}$

$.°. \:h_2\:\:=\:\:9$