Math, asked by sajangupta1964, 9 months ago

Please please help me about this question please I need ur help.
Question number 3 , 4
And if u need any kind of formula ask me about that I will give u.
This is a question from chapter 2 polynomials class 10

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Answers

Answered by DrNykterstein
1

3)

Zeroes are 2, -3 and 4

sum of zeroes = 2 - 3 + 4

==> sum of zeroes = 4 - 1

==> sum of zeroes = 3

product of zeroes = 2 × -3 × 4

==> -24

sum of the product of zeroes taken two at a time = 2×-3 + -3×4 + 4×2

==> -6 - 12 + 8

==> -18 + 8

==> -10

p(x) = x³ - ( sum of zeroes)x² + (sum of the product of zeroes taken two at time)x - (product of zeroes)

==> p(x) = x³ - (3)x² + (-10)x - (-24)

==> p(x) = - 3x² - 10x + 24

4)

Zeroes are 1/2, 1 and -3

sum of zeroes = 1/2 + 1 - 3

==> sum of zeroes = 3/2 - 3

==> sum of zeroes = -3/2

product of zeroes = 1/2 × 1 × -3

==> -3/2

sum of the product of zeroes taken two at a time = 1/2×1 + 1×-3 + -3×1/2

==> 1/2 - 3 - 3/2

==> -5/2 - 3/2

==> -4

p(x) = x³ - ( sum of zeroes)x² + (sum of the product of zeroes taken two at time)x - (product of zeroes)

==> p(x) = x³ - (-3/2)x² + (-4)x - (-3/2)

==> p(x) = x³ + 3/2x² - 4x + 3/2

Multiply p(x) by 2

==> p(x) = 2x³ + 3x² - 8x + 3

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