Question

Please refer to the attachment​

Answer 1

Answer :

Number are 4 & 5.

Step-by-step explanation:

Let one number be x

Then, second number = 9-x

A. T. Q

Sum of their squares is equal to 41

Then,

${x}^{2} + ({9 - x})^{2} = 41$

${x}^{2} + {x}^{2} + 81 - 18x = 41$

$2 {x}^{2} - 18x = 41 - 81$

$2 {x}^{2} - 18x = - 40$

$2 {x}^{2} - 18x + 40 = 0 \\ 2( {x}^{2} - 9x + 20) = 0$

${x}^{2} - 9x + 20 = 0$

☆ From Splitting Method.

${x}^{2} - 4x - 5x + 20 = 0 \\ x(x - 4) - 5(x - 4) = 0 \\ (x - 5)(x - 4)$

$\huge{\it {\underline{\underline{\red{\bold {So, \:one\:number \:is\: 5}}}}}}$

$\huge{\it {\underline{\underline {\red{\bold {and\:another \:number \:is \:4}}}}}}$

Thank You.

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