please sen the answer quickly
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ɢɪᴠᴇɴ:
- a = 7-4√3 .
ᴛᴏ ғɪɴᴅ:
- The value of √a + 1/√a.
ᴀɴsᴡᴇʀ:
Firstly it's given that a = 7-4√3
So, 1/a = 1/7-4√3
Let's rationalise the denominator,
=> 1/a = 1 / 7-4√3.
=> 1/a = 1 ( 7+4√3)/(7-4√3)(7+4√3).
=> 1/a = 7+4√3 / 7² - (4√3)².
=> 1/a = 7+4√3 / 49-48.
=> 1/a = 7+4√3 .
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Let , 1/√a + √a = x .
=> 1/√a + √a = x .
=> ( 1/√a + √a ) ² = x².
=> (1/√a)² + (√a)² + 2 × 1/√a × √a = x².
=> 1/a + a +2 = x².
=> (7-4√3)+(7+4√3) = x²
=> 7 + 7 + 2 = x².
=> x² = 16.
=> x = √16.
=> x = ± 4.
Hence the required answer is ±4.
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