Question

Please send the answer with solution

If p= -2
q= -1
r=3

Then the question is in the photo

Answer 1

Value = 3p²q + 5pq² + 2pqr

→ 3(-2)²×-1 + 5(-2)(-1)² + 2(-2)(-1)(3)

→ 3 × 4 × -1 + 5 × -2 × 1 + 2 × -2 × -1 × 3

→ -12 -10 + 12 = -10

:)

Answer 2

Answer:

= -10

Solution:

Considering the given values as :-

• p = -2
• q = -1
• r = 3

Given Equation :-

• 3p²q + 5pq² + 2pqr

Let's Solve :-

=> 3p²q + 5pq² + 2pqr

=> 3(-2)² (-1) + 5(-2)(-1)² + 2(-2)(-1)(3)

=> 3 × 2² × (-1) + 5 × (-2) × 1 + 12

=> 3 × 2² × (-1) + 5 × (-2) + 12

=> -3 × 2² × 1 × 5 × (-2) + 12

=> -3 × 4 + 5 × (-2) + 12

=> -3 × 4 - 10 + 12

=> -12 - 10 + 12

=> -10