Question

please solve 5th question

Answer 1

here is ur answer......

Answer 2

$\huge{\bold{\boxed{\boxed{Answer:-}}}}$

Question is :

$\mathsf{\dfrac{16×2^{n+1}-8×2^{n}}{16×2^{n+2}-4×2^{n+1}}}$

=$\mathsf{\dfrac{16×2^{n+1}-2^{3}×2^{n}}{16×2^{n+2}-2^{2}×2^{n+1}}}$

Now , Using $\bold {\boxed{\dfrac{a^{m}}{a^{n}}=a^{m-n}}}$

=$\mathsf{16^{1-1}×2^{n+1-(n+2)}-2^{3-2}×2^{n-(n+1)}}$

=$\mathsf{16^{0}×2^{n+1-n-2}-2^{1}×2^{n-n-1}}$

=$\mathsf{1×2^{-1}-2×2^{-1}}$

Now,We have to bring the like terms together

=$\mathsf{(1-2)×2^{-1}}$

=$\mathsf{-1×2^{-1}}$

=$\mathsf{-2^{-1}}$

Using,$\bold {\boxed {a^{-m}=\dfrac{1}{a^{m}}}}$

=$\mathsf{-\dfrac{1}{2}}$

❤hope it helps you ❤

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