Question

A10 grams bullet is fired with some velocity into a block of mass of 0.40 gram suspended freely the bullet gets into the block and block rises through a point what is the velocity with which the block Struck the point

Answer 1

The kinetic energy of the bullet will be copmletely transfered in to the block as it will be equal to its potential energy

1/2 mv^2 = mgh

1/2*10*10^-3*v^2= 0.4*10^-3*9.8*2

v^2=7.84/5

v=√1.568

=1.25 m/s

Answer 2

kinetic energy of a bullet will be penetrated and struck into block as it will be equal to it's potential energy
1/2mv²=mgh
1/2*10*10^-3*v²=0.4*10^-3*9.8*2
v^2=7.84/5
v=✓1.568
=1.25m/s