please solve above sums and send me
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22.. [x^2-x-6]=x+2
x^2-x-x-6-2=0
x^2-2x-8=0
x^2-4x+2x-8=0
x(x-4)+2(x-4)=0
(x-4)(x+2)=0
x=4,-2
is your answer
x^2-x-x-6-2=0
x^2-2x-8=0
x^2-4x+2x-8=0
x(x-4)+2(x-4)=0
(x-4)(x+2)=0
x=4,-2
is your answer
sanjay12340:
4 is given answer
not 3 frnd
wrong diya hoga
no its right
kk anyway thanks
ab dekh lo
kk
sum of roots should be 4 see question
here 4+-2=2 but not 4
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