Question

please solve b: part)..thanks:-_​

Answer 1

(A) Current in AB

I = (E) / (r + 15 r) = (E) / (16 r)

Potential gradient

K = (15 rI) / (600)

  = (15 r) / (600) xx (E) / (16r)

  = (E) / (640)

Let E//2 be balanced at `l`then,

(E) / (2) = kl = (E) / (640)l

          = 320 cm ...✔

(B) Let potential at C be zero & at A be x.

Then applying kirchhoff's first law at C. We get,

(x - 0) / (14r) + ((x - E)//(2 - 0)) / (r) + ((x - E - 0)) / (2r) = 0

or x = (14 E) / (22)

I_(g) = (x - (E) / (2)) / (r)

     = (((14 E) / (22)) - (E) / (2)) / (r)

     = (3E) / (22r) ...✔

Answer 2

Please mark my answer as the brainliest because I need 3 more brainliest answers to get Virtuoso please help me if you are kind