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(i)We know that angles if a rohmbus= 90 degrees
angle x= 90- 48= 42 degrees.
(ii) angle ABC forms a triangle and the sum of all angles of a triangle= 180 degrees.
Therefore 3x+4x+42= 180 degrees
7x+42=180 degrees.
7x= 180-42= 138
x= 138/7= 19.7= 20 degrees
(iii) angle ACD forms a triangle and sum of all angles of a triangle= 180 degrees and it is co- interior with angle x. Co- interior angles are equal.
Therefore angle ACD= 42 degrees..
Thanks for asking!
angle x= 90- 48= 42 degrees.
(ii) angle ABC forms a triangle and the sum of all angles of a triangle= 180 degrees.
Therefore 3x+4x+42= 180 degrees
7x+42=180 degrees.
7x= 180-42= 138
x= 138/7= 19.7= 20 degrees
(iii) angle ACD forms a triangle and sum of all angles of a triangle= 180 degrees and it is co- interior with angle x. Co- interior angles are equal.
Therefore angle ACD= 42 degrees..
Thanks for asking!
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