Question

please solve fast, ..........​

Answer 1

$\sf{ \bold { Given \: - }} \\ \\ \sf{ \bold {\dfrac{ x^2 + 1 }{ x } = 3 \dfrac{ 1 }{ 3 } }} \\ \\ \sf{ \bold { \& x > 1 }} \\ \\ \sf{ \bold { Solution \: - }} \\ \\ \sf{ \bold {\dfrac{ x^2 + 1 }{ x } = 3 \dfrac{ 1 }{ 3 } }} \\ \\ \sf{ \bold { \implies { x + \dfrac{ 1 }{ x } = 3 \dfrac{ 1 }{ 3 } }}} \\ \\ \sf { \bold { \implies { x + \dfrac{ 1 }{ x } = \dfrac{ 10 }{ 3 } }}} \\ \\ \sf{ \bold { Squaring \: this \: - }} \\ \\ \sf{ \bold { \implies { x^2 + \dfrac{ 1 }{ x^2 } = \dfrac{ 100 }{ 9 } }}} \\ \\ \sf{ \implies{ \bold { x^2 + \dfrac{ 1 }{ x^2 } - 2 = \dfrac{ 100 }{ 9 } - 2 }}} \\ \\ \sf{ \implies { \bold { { ( x - \dfrac{1}{ x } ) }^2 = \dfrac{ 82 }{ 9 } }}} \\ \\ \sf{ \implies { \bold { x - \dfrac{1}{ x } = \dfrac{ \sqrt[2]{82} }{ 3 } }}} \\ \\ \sf{ \implies { \bold { Cubing \: the \: above \: expression \: - }}} \\ \\ \sf{ \bold { \implies { x^3 - \dfrac{ 1 }{ x^3 } - \sqrt[2]{82} = \dfrac{ {(82)}^{ \frac{3}{2} } }{ 27 } }}} \\ \\ \sf{ \bold { \implies { x^3 - \dfrac{ 1 }{ x^3 } = \dfrac{ {(82)}^{ \frac{3}{2} } }{ 27 } + \sqrt[2]{82} }}} \\ \\ \sf{ \bold { This \: is \: the \: required \: answer \: . }}$

Answer 2

Answer:

Hey

I am Divya

Please call me Divi