Question

please solve fast x power 4- 1​

Answer 1

Answer:

x^4-1=(x^2+1)(x+1)(x-1)

using complex numbers

x^4-1=(x+ib)(x-ib)(x+1)(x-1)

Explanation:

we make use of the difference of squares

a^2-b^2=(a+b)(a-b)

x^4-1=(x^2+1)(x^2-1)

we can use dos for the second bracket once more

x^4-1=(x^2+1)(x+1)(x-1)--(1)

Step-by-step explanation:

Answer 2

Answer:

By using formula (a)^2-(b)^2=(a-1)(a+2)

So, $\large\bf\purple{Here\:is\:your\:answer}$

x^4-1=(x^2)^2-(1)^2

=(x^2+1)(x^2-1)

=(x^2+1)((x)^2-(1)^2)

=(x^2+1)(x+1)(x-1) ans.

$<marquee>$☺️☺️☺️☺️ Hope it will help you ✌️✌️✌️