please solve I Kant find the answer
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20-
diagonal = a√2= 5√2
a= 5m where a is side of square
Area = a² = 5×5 = 25m²
perimeter =4a = 5×4 =20 m
21-
a√2=12
so a = 6√2
area = a² =( 6√2)² = 6×6×2=72cm²
perimeter = 4a = 4×6√2= 24√2cm
22-
a²= 32 then a = √32= 4√2
diagonal = a√2 = 4√2 × √2 = 8 m
diagonal = a√2= 5√2
a= 5m where a is side of square
Area = a² = 5×5 = 25m²
perimeter =4a = 5×4 =20 m
21-
a√2=12
so a = 6√2
area = a² =( 6√2)² = 6×6×2=72cm²
perimeter = 4a = 4×6√2= 24√2cm
22-
a²= 32 then a = √32= 4√2
diagonal = a√2 = 4√2 × √2 = 8 m
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