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area of above structure = area of square + area of semicircle - area of right angle ∆
area of square = (edge length )² = (10)²= 100 cm²
area of semicircle = πr²/2 = π(10/2)²/2
= 25π/2 cm²
area of right angle ∆ = 1/2× height × base =1/2 × 8 × 6 = 24 cm²
so, area of above daigram = 100cm² +25π/2 cm² -24 cm²
=( 76 + 25π/2 ) cm²
area of square = (edge length )² = (10)²= 100 cm²
area of semicircle = πr²/2 = π(10/2)²/2
= 25π/2 cm²
area of right angle ∆ = 1/2× height × base =1/2 × 8 × 6 = 24 cm²
so, area of above daigram = 100cm² +25π/2 cm² -24 cm²
=( 76 + 25π/2 ) cm²
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