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Angle A + Angle B + Angle C = 180 (sum angle property)
30+60 + Angle B + 70 = 180
160 + Angle B = 180
Angle B = 20
In triangle ACD
A + C + c = 180
60 + 70 + c = 180
c + 130 = 180
c = 50
a + 30 = c (exterior angle property)
a+ 30 = 50
a = 20
In triangle ABD
a + b + 30 = 180
30 + 20 + b = 180
50 + b = 180
b = 130
Answered by
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Answer:
In triangle ADC,
⇒ b=60+70
⇒ b = 130
Now, in triangle ABD,
⇒ a+b+30 = 180
⇒ a = 180−30o - 130
⇒ a = 20
Also,
∠ADC=∠BAD+∠ABD .... Exterior angle property
⇒ c=30+a
⇒ c=30+20
⇒ c=50
Therefore,
a=20, b=130, c=50
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