Math, asked by geetachamoli252, 7 hours ago

please solve it asap ​

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Answered by hemantsinha2005
0

Answer:

Angle A + Angle B + Angle C = 180 (sum angle property)

30+60 + Angle B + 70 = 180

160 + Angle B = 180

Angle B = 20

In triangle ACD

A + C + c = 180

60 + 70 + c = 180

c + 130 = 180

c = 50

a + 30 = c (exterior angle property)

a+ 30 = 50

a = 20

In triangle ABD

a + b + 30 = 180

30 + 20 + b = 180

50 + b = 180

b = 130

Answered by KshitizPandey01
0

Answer:

In triangle ADC,

⇒ b=60+70

⇒ b = 130

Now, in triangle ABD,

⇒ a+b+30 = 180

⇒ a = 180−30o - 130

⇒ a = 20

Also, 

∠ADC=∠BAD+∠ABD  .... Exterior angle property

⇒ c=30+a

⇒ c=30+20

⇒ c=50

Therefore,

a=20, b=130, c=50

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