Question

please solve it for class 10 th maths polynomial as divide obtain all the zeroes of
$x {}^{4} - 7 {x}^{2} + 12 \:$
if it is given that two of its zeroes are
$\sqrt{3 } \: and \: - \sqrt{3}$

please solve​

Answer 1

Answer:

+2, -2

Step-by-step explanation:

Given Equation is f(x) = x⁴ - 7x² + 12.

Given Zeroes are ±√3.

= (x - √3)(x + √3)

= x² - 3 is also a factor.

Now, Divide f(x) by x² - 3.

Long Division Method:

x² - 3) x⁴ - 7x² + 12(x² - 4

          x⁴ - 3x²

          --------------------

                   -4x² + 12

                   -4x² + 12

            -----------------------

                                    0

Now, we have to find the zeroes.

⇒ x² - 4 = 0

⇒ x² = 4

⇒ x = ±2

∴ Zeroes of the polynomial are : ±2.

Hope it helps!

Answer 2

The answer is explained.

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