Question

please solve it I SHALL make you brainlist

Answer 1

(7).

Let one number be 'x'.

Then the other number will be 'x + 10'

Given that Sum is 52.

⇒ x + x + 10 = 52

⇒ 2x = 42

⇒ x = 21.

Then

⇒ x + 10 = 31.

Therefore, The numbers are 21 and 31.

(8)

Let the breadth of the rectangle be 'x'.

Then the length of the rectangle will be x + 20 cm.

We know that perimeter of rectangle = 2(l + b)

⇒ 100 = 2(x + x + 20)

⇒ 100 = 2(2x + 20)

⇒ 100 = 4x + 40

⇒ 60 = 4x

⇒ x = 15.

Then:

⇒ x + 20 = 35.

Therefore:

⇒ The length of the rectangle = 35 cm.

⇒ The breadth of the rectangle = 15 cm.

Hope it helps!

Answer 2

Hey there !!


▶ Question 7 :-)

→ One number is 10 more than the other. If their sum is 52, find the numbers.


▶ Solution :-)

Let the other number be x.

then, the one number = x + 10.

▶ Now, A/Q

=> x + 10 + x = 52 .

=> 2x + 10 = 52.

=> 2x = 52 - 10.

=> 2x = 42.

=> x = 42/2 .

•°• x = 21 .


Therefore, the number are 21 and 31 [ x + 10 ] .



▶ Question 8 :-)

→ The length of a rectangle is 20 cm more than its breadth. If the perimeter is 100 cm , find the dimension of the rectangle.


▶ Solution :-

Let the breadth of the rectangle be x.

Then, the length of the rectangle = 20 + x .

▶ Now,

°•° Perimeter of rectangle = 100 cm .

=> 2( l + b ) = 100 .

=> 2 ( 20 + x + x ) = 100.

=> 20 + 2x = 100/2 .

=> 2x + 20 = 50.

=> 2x = 50 - 20 .

=> 2x = 30.

=> x = 30/2 .

•°• x = 15 cm.

Therefore, the dimension of the rectangle are 35 cm [ x + 20 ] and 15 cm.


✔✔ Hence, it is solved ✅✅.

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