Question

PLEASE SOLVE ITS URGENT CORRECT ANSWER WILL GET BRAINLIST

Answer 1

Answer:

1.78

Step-by-step explanation:

In ΔABC and ΔDCE ,

∠ACD = ∠BCE

►∠ACD+∠DCB = ∠BCE+∠DCB  (adding ∠DCB each side)

►∠ACB = ∠DCE    (first angle)

∠ABC = ∠DEC  (according to ques.)   (second angle)

third angle will be equal too.

So, ΔABC and ΔDCE are similar .

Now, $\frac{area\ of\ \triangle ABC }{area\ of\ \triangle DEC } = \frac{AB^2}{DE^2} = \frac{10.4^2}{7.8^2} = 1.78$

Answer 2

$\huge \underline \bold \red {Answer}$

In ΔABC and ΔDCE ,

∠ACD = ∠BCE

►∠ACD+∠DCB = ∠BCE+∠DCB (adding ∠DCB each side)

►∠ACB = ∠DCE (first angle)

∠ABC = ∠DEC (according to ques.) (second angle)

third angle will be equal too.

So, ΔABC and ΔDCE are similar .

Now, \frac{area\ of\ \triangle ABC }{area\ of\ \triangle DEC } = \frac{AB^2}{DE^2} = \frac{10.4^2}{7.8^2} = 1.78

area of △DEC

area of △ABC

=

DE

2

AB

2

=

7.8

2

10.4

2

=1.78

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