Question

please solve my question​

Answer 1

Ⓗⓞⓛⓐ

1) threshold frequency ,

Vo = 4.5 × 10^14 Hz

2) work function = hVo

= 6.625 × 10^-34 × 4.5 × 10^14 j / 1.6 × 10^-19 eV

= 1.86 eV

✌

Answer 2

hello mate here wo go

from the graph we see that the minimum frequency at which cut off voltage increases is

$4.5 \times 10 {}^{14}$so

• the threshold frequency
• $4.5 \times {10}^{14}$
• work function=hx threshold frequency
• $2817 \times {10}^{ - 20}$=2.28ev

HOPE IT HELPS