Question

Please Solve Q4 I Will Mark U As Brainliest.

Answer 1

Hope My Answer Is Right..

Answer 2

Step-by-step explanation:

1. [tex]
5. \boxed{\bf{\frac{1}{f} =\frac{1}{v} -\frac{1}{u} }}}}
7. \begin{gathered}\longrightarrow\sf{\dfrac{1}{-10} =\dfrac{1}{v} -\dfrac{1}{-30} }\\\\\\\longrightarrow\sf{\dfrac{1}{v} =\dfrac{1}{-10} +\dfrac{1}{30} }\\\\\\\longrightarrow\sf{\dfrac{1}{v} =\dfrac{-3+1}{30} }\\\\\\\longrightarrow\sf{\dfrac{1}{v} =\cancel{\dfrac{-2}{30} }}\\\\\\\longrightarrow\sf{\dfrac{1}{v} =\dfrac{1}{-15} }\\\\\\\longrightarrow\sf{v=-15\:cm}\end{gathered}
8. ⟶
9. −10
10. 1
12. =
13. v
14. 1
16. −
17. −30
18. 1
21. ⟶
22. v
23. 1
25. =
26. −10
27. 1
29. +
30. 30
31. 1
34. ⟶
35. v
36. 1
38. =
39. 30
40. −3+1
43. ⟶
44. v
45. 1
47. =
48. 30
49. −2
54. ⟶
55. v
56. 1
58. =
59. −15
60. 1
63. ⟶v=−15cm
68. \boxed{\bf{M \:A \:G \:N\: I \:F \:I \:C\: A\: T \:I \:O\: N :}}
69. MAGNIFICATION:
73. \begin{gathered}\mapsto\sf{m=\dfrac{Height\:of\:image\:(I)}{Height\:of\:object\:(O)} =\dfrac{Distance\:of\:image}{Distance\:of\:object} =\dfrac{v}{u} }\\\\\\\mapsto\sf{m=\cancel{\dfrac{-30}{-15}} }\\\\\\\mapsto\bf{m=2\:cm}\end{gathered}
74. ↦m=
75. Heightofobject(O)
76. Heightofimage(I)
78. =
79. Distanceofobject
80. Distanceofimage
82. =
83. u
84. v
87. ↦m=
88. −15
89. −30
94. ↦m=2cm
98. Thus;