Question

Please solve question no.9
I will mark it as branliest answer

Answer 1

HEY BUDDY..!!

HERE'S THE ANSWER...!!!

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#1. log x log ( xyz ) = 48

#2. log y log ( xyz ) = 12

#3. log z log ( xyz ) = 84

⏺️ Now dividing eq 1 and 2

=> log x log ( xyz ) / log y log ( xyz ) = 48 / 12

=> log x / log y = 4

=> log x = 4 log y

=> log x = log y^4

=> x = y^4

⏺️ Now divide eqn 3 by 2

=> log z log ( xyz ) / log y log ( xyz ) = 84 / 12

=> log z / log y = 7

=> log z = 7 log y

=> z = y^7

Now

=> z = y^4 . y^3

=> z = x . y^3

HOPE HELPED..

GOOD NIGHT..

:-)