Question

Please solve question number 28

Answer 1

see as line bc||de then angle BAD =ABC and CAE=BCA . (alt int angles)
thus ABC > BCA
thus AC > AB
By using converse of theorem : The greater side has the greater angle opposite to it.

Answer 2

In quad ABED, we have AB||DE and AB = DE
ABED is a parallelogram.
AD||BE and AD = BE
Now, in quad ACFD, we have
AC||FD and AC = FD
ACFD is a parallelogram.
AD||CF and AD = CF
AD = BE = CF and CF||BE
Now, in quad BCFE,
BE = CF and BE||CF.
BCFE is a parallelogram.
BC = EF and BC||EF
Hence, proved.