Question

please solve question of class 10th physics

Answer 1

hello friend...!!

according to the given question,

1) total resistance :

• 6 ohm and 3 ohm are parallel so ,

1 / R = 1 / R1 + 1 / R2 .

1 / R = 1 / 6 + 1 / 3 = 3 / 6

implies R = 6 / 3 = 2 --------( 1 )

now this 2 ohm is series with 4 ohm there fore the effective resistance is

R = 2 + 4 = 6 ohm.

2) total current in the circuit :

we know that V = IR

implies, I = V / R

therefore I = 12 / 6 = 2 A.
there fore the total current in the circuit is 2A.

3) potential difference across each resistor :

a) across 4ohm
v = I R
implies, V = 2 X 4 = 8 v.

b) across 6ohm,
V = 2 X 6 = 12v.

c) across 3ohm
V= 2 X 3 = 6v.


4)current through each resistor :

I = V / R

a) I across 4ohm is
I = 8 / 4 = 2A

b) I across 6ohm
I = 12 / 6 = 2A

c) I across 3ohm
I = 6 / 3 = 2A.

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hope it helps...!!