Question

please solve question (v)​

Answer 1

Step-by-step explanation:

I) x²+y²+2xy-z²= (x+y)²-z²

which is same as a²-b²=(a+b)(a-b)

(x+y)²-z²=(x+y+z)(x+y-z)

ii) a² -b²-c²-2bc = a² -(b²+c²+2bc)

=a²-(b+c)²

=(a+b+c)(a-b-c)

iii) x⁴-14x²y²+y⁴= x⁴+2x²y²+y⁴ -16x²y²

=(x²+y²)² -(4xy)²

=(x²+y²+4xy)(x²+y²-4xy)