please solve question (v)
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Step-by-step explanation:
I) x²+y²+2xy-z²= (x+y)²-z²
which is same as a²-b²=(a+b)(a-b)
(x+y)²-z²=(x+y+z)(x+y-z)
ii) a² -b²-c²-2bc = a² -(b²+c²+2bc)
=a²-(b+c)²
=(a+b+c)(a-b-c)
iii) x⁴-14x²y²+y⁴= x⁴+2x²y²+y⁴ -16x²y²
=(x²+y²)² -(4xy)²
=(x²+y²+4xy)(x²+y²-4xy)
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