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In triangle ABD & triangle BCD
AB = DC ( opp. sides of a parallelogram are parallel and equal )
AD = BC ( opp. sides of parallelogram are parallel and equal)
BD = BD ( common )
therefore, ABD =~ BCD by SSS rule
Hence proved
AB = DC ( opp. sides of a parallelogram are parallel and equal )
AD = BC ( opp. sides of parallelogram are parallel and equal)
BD = BD ( common )
therefore, ABD =~ BCD by SSS rule
Hence proved
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