Math, asked by shaivi61, 8 months ago

Please Solve The Given Question

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Answered by hiyabhatt8126

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Answered by priyarathore2006

Given BE is a altitude, so,AEB=CEB=90°.Also, CF is a altitude, so,AFC=BFC=90°.Also,BF=CF. In BFC and CBE= BFC=CEB=90°(Both90°) =BC=CB(Common) =FC=EB(From(3)) =BCF=CBE(RHS congruence rule) =FBC=ECB(CPCT) So,ABC=ACB AB=AC(Sides opposite to equal angles is equal) So,ABC is an isoceles triangle.

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