Question

please solve these 3 for me....

1.)Find the value of k, if (1 - 1) is a solution of
the equation 3x - ky = 8. Also, find the
coordinates of another point lying on its
graph.

2.)Draw the graph of linear equation
2x + 5y = 13. Check whether (4,1) is a
solution of the given equation.

3.) Write linear equation such that each point
on its graph has ordinate 3 times its
abscissa.
​

Answer 1

Step-by-step explanation:

(1)

(1 - 1) is a solution of the equation 3x - ky = 8.

Therefore, 3(1)-k(-1)=8

=>k=8-3=5

=>k=5

(2)

2x + 5y = 13

$x = \frac{13 - 5y}{2}$

The four solutions are,

• (4,1)
• (9,-1)
• (-1,3)
• (-6,5)

Now put these values on the mm graph and you will find a straight line..... You can see (4,1) is a solution of the equation and remember don't put this point on the graph Coz you have to find this point on the straight line after drawing it...... So takes the last 3 points to draw the graph and then find the point (4,1) as you can see this point lies on the straight line....... Think you understood.

(3)

Ordinate=3*abscissa

Y=3X

3X-Y=0

Answer 2

Answer:

Step-by-step explanation: