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Answer:
m∠ABC = 130° , m∠BCD = 120°
Step-by-step explanation:
given :
AD || BC , m∠DAP = 25° & m∠ADP = 30°
AP & DP are bisectors of ∠A & ∠B respectively.
to find :
m∠ABC & m∠BCD
solution :
m∠A = 2 × m∠DAP .........
bisector of devides angle equally
:. m∠A = 2 × 25° = 50°
m∠D = 2 × m∠ADP .........
bisector of devides angle equally
:. m∠D = 2 × 30° = 60°
here AD || BC & AB is transversal ,
m∠A + m∠B = 180° ......interior angles theorem
50° + m∠B = 180°
:. m∠B = 180° - 50° = 130°
here AD || BC & CD is transversal ,
m∠C + m∠D = 180° ......interior angles theorem
50° + m∠C = 180°
:. m∠B = 180° - 60° = 120°
hence proved.
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