Question

please solve this correctly..and tell me that can this again be simplified?​

Answer 1

Answer:

d/dx log(tan2x)= 1/tan2x*sec^2x*2

Step-by-step explanation:

firstly we do derivative of log(tan2x) and derivatve of logx = 1/x

and here x=2x

and derivative of log(tan2x) multiplied by d/dx of tan2x

so answer is :

1/tan2x*d/dx tan2x

and now we find d/dx of tan2x and this should multilied by d/dx of 2x

so answer become:

1/tan2x*sec^2x*2

hope it will help you!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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