Question

Please Solve this Fraction
$\frac{ - 7}{18} \times \frac{15}{ - 7} - 1 \times \frac{1}{4} + \frac{1}{2} \times \frac{1}{4}$
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Answer 1

Step-by-step explanation:

Date 6/8/20 Eng 2 Hlw

Change each of the following Complex Sentences to Simple Sentences each containing an Adjective Clause:

1. He shot a tiger which was the horror of the district.

Ans: He shot the horror tiger of the district....

2. This is the book which belongs to me.

Ans:This is my book...

3. I saw a man who was blind.

Ans:I saw a blind man...

4. This is the bottle which is used for water.

Ans:This is the water bottle...

5. I found the book which I had lost.

Ans :I found the lost book..

6. The boy who stood first got the prize.

Ans:The rank holder boy got the prize...

7. I watched a movie which was so exciting.

Ans: I watched an exciting movie..

8. A stone that rolls does not gather moss.

Ans : A rolling stone does not gather moss..

9. A dog that barks does not bite.

Ans:A barking dog does not bite..Date 20/8/20 Eng2 hlw

Convert the following Complex Sentences to Simple Sentences using an Adverb Clause:

1. An honest boy speaks as he thinks.

Ans: An honest boy speaks his thoughts...

2. I shall give you my horse if you give me your silver.

Ans:I shall give you my horse on your giving silver...

3. Robinson Crusoe was puzzled when he discovered the print of a foot on the sand.

Ans:Robinson Crusoe was puzzled on discovering the print of a foot on the sand...

4. Though the sky falls, he will not be frightened.

Ans: The sky falling cannot frightened him...

5. I will buy it,cost what it may.

Ans: I don't care the cost to buy it....

6. Iam surprised that you should believe such nonsense.

Ans: I am suprised you to believe such nonsense..

7. He is so weak that he cannot stand.

Ans: He is too weak to stand..

8. No sooner did she see him than she broke into a sprint.

Ans:As soon as he saw him she broke into a sprint...

Answer 2

$\large\underline{ \underline{ \sf \maltese{ \: Question:- }}}$

• $\bigg(\frac{ - 7}{18} \times \frac{15}{ - 7} \bigg) - \bigg(1 \times \frac{1}{4} \bigg) + \bigg(\frac{1}{2} \times \frac{1}{4} \bigg)$

$\large\underline{ \underline{ \sf \maltese{ \: Solution:- }}}$

$\begin{gathered}\begin{gathered}\begin{gathered}: \implies \underline\blue{ \boxed{\displaystyle \sf \bold\orange{\: \bigg(\frac{ - 7}{18} \times \frac{15}{ - 7} \bigg) - \bigg(1 \times \frac{1}{4} \bigg) + \bigg(\frac{1}{2} \times \frac{1}{4} \bigg) }} }\\ \\\end{gathered}\end{gathered}\end{gathered}$

$\qquad \quad {:} \longrightarrow \sf{\sf{ \bigg(\frac{ - 7}{18} \times \frac{15}{ - 7} \bigg) - \bigg( \frac{1}{1} \times \frac{1}{4} \bigg) + \bigg(\frac{1}{2} \times \frac{1}{4} \bigg) }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{ \frac{ - 7 \times 15}{18 \times \: - 7} - \frac{1 \times 1}{1 \times 4} + \frac{1 \times 1}{2 \times 4} }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{ \frac{ \cancel \pink{ - 7} \times \cancel \green{15}}{ \cancel \green{18 } \times \: \cancel \pink{ - 7}} \: - \frac{1 \times 1}{1 \times 4} + \frac{1 \times 1}{2 \times 4} }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{ \frac{ 1 \times5}{6 \times \: 1} \: - \frac{1 \times 1}{1 \times 4} + \frac{1 \times 1}{2 \times 4} }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{ \frac{5}{6} \: - \: \frac{1}{4} \: + \: \frac{1}{8} }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{ \frac{5}{6} \: + \: \frac{ - 1}{4} \: + \: \frac{1}{8} }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{ \frac{5 \times 4 + ( - 1) \: \times 6 \: + 1 \: \times 3}{24} }}$

$\qquad \quad {:} \longrightarrow \sf{\sf \frac{20 \: + \: ( - 6) \: + \: 3}{24} }$

$\qquad\quad {:} \longrightarrow \underline \red{\boxed{\sf{ \: \frac{17}{24} }}}$

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$\bf \therefore \; Value \: of \: Fraction =\frac{17}{24}$

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More For Knowledge:-

$\boxed{\begin{minipage}{6 cm}\bf{\dag}\:\:\underline{\textsf{Fraction Rules :}}\\\\\bigstar\:\:\sf\dfrac{A}{B} + \dfrac{B}{C} = \dfrac{A+B}{C} \\\\\bigstar\:\:\sf{\dfrac{A}{B} - \dfrac{B}{C} = \dfrac{A-B}{C}}\\\\\bigstar\:\:\sf\dfrac{A}{B} \times \dfrac{C}{D} = \dfrac{AC}{BD}\\\\\bigstar\:\:\sf\dfrac{A}{B} + \dfrac{C}{D} = \dfrac{AD}{BD} + \dfrac{BC}{BD} = \dfrac{AD+BC}{BD} \\\\\bigstar\:\:\sf\dfrac{A}{B} - \dfrac{C}{D} = \dfrac{AD}{BD} - \dfrac{BC}{BD} = \dfrac{AD-BC}{BD}\\\\\bigstar \:\:\sf \dfrac{A}{B} \div \dfrac{C}{D} = \dfrac{A}{B} \times \dfrac{D}{C} = \dfrac{AD}{BC}\end{minipage}}$

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