Please solve this friend plzz
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darkmatter77:
Please give a swer friend
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In ∆ADB and ∆ADC
AD = AC ( Given)
<DAB = <DAC ( Angle bisector)
AD = AD (common)
Therefore ∆ADB is congruent to ∆ADC ( by S.A.S)
Therefore BD = CD ( C.P.C.T.C)
AD = AC ( Given)
<DAB = <DAC ( Angle bisector)
AD = AD (common)
Therefore ∆ADB is congruent to ∆ADC ( by S.A.S)
Therefore BD = CD ( C.P.C.T.C)
Hey friend thanks you
Your welcome ☺
Friend where you live plz tell me
I just want to ask you why are asking this to me ??
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