Question

please solve this it is urgent and fast​

Answer 1

$\huge\underline\bold\red{AnswEr}$

${x}^{2} + 5x + 5 = 00$

solution:-

$= > {(x - 1)}^{2} - 3x + 4 \\ .......using \: formula \: of \: \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ hence... \\ = > {x}^{2} - 2x + 1 - 3x + 4 \\ = > {x}^{2} + 5x + 5$

Answer 2

Answer:

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