please solve this maths problem...
Find the value of cos(-1710)
its urgent for 100 points
Answers
Answered by
5
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☬ YOUR ANSWER ☬
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As we know that values of cosx repaets itself after an interval of 2Π or 360°
so,
⏩cos(-1710) =
⏩ cos (-1710 +5•360°)
⏩cos(-1710 +1800 )
⏩cos(90)
⏩=0
╒══════════════════════╕
☬ THANKS! @Brainlyconquerer ☬
╘══════════════════════╛
☬ YOUR ANSWER ☬
╘═════════════════════╛
As we know that values of cosx repaets itself after an interval of 2Π or 360°
so,
⏩cos(-1710) =
⏩ cos (-1710 +5•360°)
⏩cos(-1710 +1800 )
⏩cos(90)
⏩=0
╒══════════════════════╕
☬ THANKS! @Brainlyconquerer ☬
╘══════════════════════╛
Answered by
3
Hello mate,
This can be solved by
Equational and rounding off in quadrant values
We all are aware by the fact that Cos x values are repitative at an interval of 360°
=cos(-1710 + 360*360*360*360*360)
=cos(-1710 +1800)
=cos(90)
=0
This can be solved by
Equational and rounding off in quadrant values
We all are aware by the fact that Cos x values are repitative at an interval of 360°
=cos(-1710 + 360*360*360*360*360)
=cos(-1710 +1800)
=cos(90)
=0
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