Question

please solve this please and take a pic of answer and then send me .solve this please solve this please solve this please solve this please solve this please solve this please solve this please solve this ​ and ​

Answer 1

$Given \:\frac{x+2}{6} + \frac{x-3}{3} = x$

/* Multiplying both sides by 6, we get */

$\implies \frac{6(x+2)}{6} + \frac{6(x-3)}{3} = 6x$

$\implies x + 2 + 2(x-3) = 6x$

$\implies x + 2 + 2x-6 = 6x$

$\implies 3x-4= 6x$

$\implies -4= 6x - 3x$

$\implies -4 = 3x$

$\implies \frac{-4}{3} = x$

Therefore.,

$\red{ x }\green { = \frac{-4}{3}}$

Verification:

$LHS = \frac{\frac{-4}{3} + 2}{6} + \frac{\frac{-4}{3} - 3}{3}$

$= \frac{\frac{-4+6}{3}}{6} + \frac{\frac{-4-9}{3}}{3}\\= \frac{2}{3} \times \frac{1}{6} + \frac{-13}{3} \times \frac{1}{3} \\= \frac{2}{18} - \frac{13}{9} \\= \frac{1}{9} - \frac{13}{9}\\= \frac{1-13}{9} \\= \frac{-12}{9}\\= \frac{-4}{3} \\= x \\= RHS$

•••♪