Question

please solve this problem

Answer 1

Steps

$a^2b\left(a-b^2\right)+ab^2\left(4ab-2a^2\right)-a^3b\left(1-2b\right)$

$\mathrm{Expand}\:a^2b\left(a-b^2\right):\quad a^3b-a^2b^3$

$=a^3b-a^2b^3+ab^2\left(4ab-2a^2\right)-a^3b\left(1-2b\right)$

$\mathrm{Expand}\:ab^2\left(4ab-2a^2\right):\quad 4a^2b^3-2a^3b^2$

$=a^3b-a^2b^3+4a^2b^3-2a^3b^2-a^3b\left(1-2b\right)$

$\mathrm{Expand}\:-a^3b\left(1-2b\right):\quad -a^3b+2a^3b^2$

$=a^3b-a^2b^3+4a^2b^3-2a^3b^2-a^3b+2a^3b^2$

$\mathrm{Simplify}\:a^3b-a^2b^3+4a^2b^3-2a^3b^2-a^3b+2a^3b^2:\quad 3a^2b^3$

And your answer is

$=3a^2b^3$

Answer 2

this is the answer of ur question
hope it will help u