Please solve this problem
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AB = AC + BC
( AC = BC )
AB = AC + AC
AB = 2 AC
1 / 2 AB = AC
hence , proved..
Figure is in the attachment ..
part 2 of question..
Suppose C and C' are two mid points of segment AB.
Then AC = AB.
and AC' = AB.
AC = AC' [Things which are equal to the same thing are equal to one another.]
This is possible only when C and C' coincide.
Hence every line segment has one and only one midpoint.
( AC = BC )
AB = AC + AC
AB = 2 AC
1 / 2 AB = AC
hence , proved..
Figure is in the attachment ..
part 2 of question..
Suppose C and C' are two mid points of segment AB.
Then AC = AB.
and AC' = AB.
AC = AC' [Things which are equal to the same thing are equal to one another.]
This is possible only when C and C' coincide.
Hence every line segment has one and only one midpoint.
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