Physics, asked by dityashahni, 1 year ago

please solve this problem!

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Answers

Answered by reyan12
1
Match the ans....is this correct
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dityashahni: yes
reyan12: okyy
dityashahni: can u explain!
reyan12: this is formula based....for any time 'n' sec. the distance covered is equal to initial velocity + acceleration/2 × (2×n sec -1)
dityashahni: please!
reyan12: it helps u or not....
dityashahni: ya thanks
reyan12: ur wlcme...
Answered by rakeshmohata
4
Hope u like my process
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A formula is there to find the distance travelled by body in nth second.

 =  >  \underline{ \green{  \bold{s_{n} = u +  \frac{a}{2} (2n - 1)}}}
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Since here the body is falling freely,

=> Initial velocity (u) = 0

=> a = g = 9.8 m/s (constant term)

So,..
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=> Distance travelled in nth second is directly proportional to (2n-1)
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Now,..
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 =  > \bf  \frac{s _{1} }{ s_{2}}  =   \frac{ \blue{(2 \times 4) - 1}}{ \blue{(2 \times 5) - 1}}  =  \blue{ \frac{8 - 1}{10 - 1} } \\  \\  =  >  \bf \frac{ s_{1} }{ s_{2} }  =  \blue{ \frac{7}{9} } \\  \\  =  >  s_{1} :  s_{2} =   \underline{\blue{ \it{7 :9 }}}

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Hope this is ur required answer ❤️

Proud to help you ❤️
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