Please solve this question.
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heya.....
f(x) = -9x^4-5x^3+3x^2+4x+7
Using Descartes' rule of signs
There is one sign change so f(x) has one positive real root
f(-x) = -9(-x)^4 - 5 (-x)^3 + 3(-x)^2 + 4(-x) + 7
f(-x) = -9x^4+5x^3+3x^2-4x+7
There are two sign changes so there are 0 or 2 negative real roots
From (1) & (2) , there is only 1 or 2 real roots.
so ur option is A
tysm.....#gozmit
f(x) = -9x^4-5x^3+3x^2+4x+7
Using Descartes' rule of signs
There is one sign change so f(x) has one positive real root
f(-x) = -9(-x)^4 - 5 (-x)^3 + 3(-x)^2 + 4(-x) + 7
f(-x) = -9x^4+5x^3+3x^2-4x+7
There are two sign changes so there are 0 or 2 negative real roots
From (1) & (2) , there is only 1 or 2 real roots.
so ur option is A
tysm.....#gozmit
shantanu219:
thnx for the answer but its wrong
the answer is (D)
srry i mean (A)
i just wrote (D) by mistake
thnx bro
can u also solve my other questions
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