Question

please solve this question

Answer 1

Answer:

Step-by-step explanation:

Let EF intersect AB at M and CD at N.

<AMN=2x°

Therefore, <MND=2x°

2x=5x-51 (VERTICALLY OPPOSITE

ANGLES )

=>5x-2x=51

=>3x=51

=>x=17

Therefore,<CNF=(5x-51)°

=5*17° - 51°

=(85-51)°

=34°

y°+(5x-51)°=180° (linear pair)

=>y°+34°= 180°

=>y=146°