Please solve this question :-
(a+b√3)² = 4+7√3
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Hey there!
( a + b√3 )² = 4 + 7√3
Applying square root on both sides,
a + b √3 = √ ( 4 + 7 √3 )
Now, We will find square root of 4 + 7√3
So,
Let
√ ( 4 + 7√3 ) = √x + √y
Now, Squaring on both sides
4 + 7√3 = x + y + 2√xy
So, x + y = 4 , xy = √49*3/4 =√147/4
Now,
( x - y) ² = (x + y )² - 4xy
x - y = √ ( 16 - √147 )
Now, x = 4 + √( 16 - √147 ) /2
x + y = 4
y = 4 - 2 - √(16 - √147)/2
y = 2 - √ ( 16 - √147 ) / 2
So,
a + b √3 = √ 4 + √ (16 - 7√3 ) / 2 + √ 2 - √( 16 - 7√3 )/2
The answer will be so complex.
So, I feel there might be errors in the question.
Let's consider your question to be :
a + b √3 = 4 + 7√3
We get values as a = 4 , b = 7 .
( a + b√3 )² = 4 + 7√3
Applying square root on both sides,
a + b √3 = √ ( 4 + 7 √3 )
Now, We will find square root of 4 + 7√3
So,
Let
√ ( 4 + 7√3 ) = √x + √y
Now, Squaring on both sides
4 + 7√3 = x + y + 2√xy
So, x + y = 4 , xy = √49*3/4 =√147/4
Now,
( x - y) ² = (x + y )² - 4xy
x - y = √ ( 16 - √147 )
Now, x = 4 + √( 16 - √147 ) /2
x + y = 4
y = 4 - 2 - √(16 - √147)/2
y = 2 - √ ( 16 - √147 ) / 2
So,
a + b √3 = √ 4 + √ (16 - 7√3 ) / 2 + √ 2 - √( 16 - 7√3 )/2
The answer will be so complex.
So, I feel there might be errors in the question.
Let's consider your question to be :
a + b √3 = 4 + 7√3
We get values as a = 4 , b = 7 .
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Hope this will help you ☺☺
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