Question

please solve this question
class 9​

Answer 1

$\textsf{\large{\underline{Solution}:}}$

Given Equation:

$\rm \longrightarrow \dfrac{(2 - \sqrt{5}) + (3 + 2 \sqrt{5} ) - (4 + \sqrt{5} ) }{4} = p + q \sqrt{5}$

$\rm \longrightarrow \dfrac{2 - \sqrt{5} + 3 + 2 \sqrt{5} -4 - \sqrt{5}}{4} = p + q \sqrt{5}$

$\rm \longrightarrow \dfrac{(2 + 3 - 4) + (2 - 1 - 1) \sqrt{5} }{4} = p + q \sqrt{5}$

$\rm \longrightarrow \dfrac{1}{4} = p + q \sqrt{5}$

$\rm \longrightarrow \dfrac{1}{4} + 0 \sqrt{5} = p + q \sqrt{5}$

Comparing both sides, we get:

$\rm \longrightarrow p = \dfrac{1}{4}$

$\rm \longrightarrow q =0$

Which is our required answer.

$\textsf{\large{\underline{Answer}:}}$

• p = 1/4
• q = 0

Answer 2

Answer:

Step-by-step explanation:

p = - √5q + 2500.

q = - √5(P - 2500)/5.