Chemistry, asked by sona561, 1 year ago

please solve this question first

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Answered by Skgupta14
1
Since density of water is 1 gm/cc, 18 ml corresponds to mass m =18 g of water.
so, no. of moles corresponding to 18 g = m/A = 1, where A is molecular wt (water =18 g)
Now, 1 mole of water contains 6.022*10^23 molecules of H2O and
one molecule of H2O contains 10 electrons (i.e. There are 8 electrons in oxygen and 1 from each hydrogen so a water molecule has 10 electrons).
Hence, total no. of electrons present in 18 ml of water =10 * 6.022*10^23
= 6.022*10^24

18 mL water X 1 g/mL = 18 g water

moles H2O = 18 g / 18 g/mol = 1 mole H2O
Answered by kush193874
4

Since density of water is 1 gm/cc, 18 ml corresponds to mass m =18 g of water.

one molecule of H2O contains 10 electrons (i.e. There are 8 electrons in oxygen and 1 from each hydrogen so a water molecule has 10 electrons).

Hence, total no. of electrons present in 18 ml of water =10 * 6.022*10^23

= 6.022*10^24

18 mL water X 1 g/mL = 18 g water

moles H2O = 18 g / 18 g/mol = 1 mole H2O

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