Math, asked by 46mishra, 5 months ago

please solve this question guys ​

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Answered by jaspalsoni
0

Answer:

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Answered by nidhigautam232
1

Let the total units of work be LCM(10,15)=3

A does 30/10 = 3 units per day work

B does 30/15 = 2 units per day work

Together they do (3+2)=5 units of per day work.

Let say both of them worked for x days.

Work done by them in x days = 5x

Remaining work = 30–5x

This remaining work done by A alone in 5 days

Hence,

5*(A's work per day)= 30–5x

5*3=30–5x

x=3

A & B worked for 3 days.

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