please solve this question
I'll mark it as the BRAINLIEST ONE
Answers
hello dear here is your answer to your question========================= ==========================✌ ✌
BC²=AC²+AB²
=8²+6²
=64+36
=100
BC=10cm
Area of biggest semicircle = 1/2 * 3.14 * r²
=0.5*3.14*5*5
=0.5*78.5
=39.25 cm²
Area of 2nd Largest Semicircle = 0.5*3.14*r²
=0.5*3.14*3²
=0.5*3.14*9
=14.13 cm²
Area of smallest Semicircle = 0.5*3.14*r²
=0.5*3.14*4²
=0.5*3.14*16
=25.12 cm²
Area of Triangle = 1/2 *b*h
= 0.5*6*8
=24 cm²
Area of shaded region = (24+25.12+14.13) - 39.25
= 63.25-39.25
=24 cm²
MARK BRAINLIEST!!
Area of semi circle with AB as diameter
= pie r^2/2
= 3.14× 9/2 = 14.13
Area of semi circle with AC as diameter
= 3.14 × 16/2 = 3.14 × 8 = 25.12
AREA of semi circle with BC as diameter
BC= √6^2 + 8^2 = √36 +64 = 10
So 3.14 × 25/2 = 39.25
Area of semi circle with AB and AC as diameter = 14.13 +25.12 = 39.25
Now as semi circle with BC as diameter includes triangle ABC also
So 39.25 +39.25 - 24
54.5