Question

please solve this question

I'll mark it as the BRAINLIEST ONE​

Answer 1

hello dear here is your answer to your question========================= ==========================✌ ✌

BC²=AC²+AB²

      =8²+6²

      =64+36

       =100

BC=10cm

Area of biggest semicircle = 1/2 * 3.14 * r²

                                 =0.5*3.14*5*5

                                  =0.5*78.5

                                  =39.25 cm²

Area of 2nd Largest Semicircle = 0.5*3.14*r²

                                                     =0.5*3.14*3²

                                                   =0.5*3.14*9

                                                    =14.13 cm²

Area of smallest Semicircle = 0.5*3.14*r²

                                             =0.5*3.14*4²

                                             =0.5*3.14*16

                                             =25.12 cm²

Area of Triangle = 1/2 *b*h

                         = 0.5*6*8

                            =24 cm²

Area of shaded region = (24+25.12+14.13) - 39.25

                                    = 63.25-39.25

                                    =24 cm²

MARK BRAINLIEST!!

Answer 2

Area of ABC = 1/2 × 6× 8 = 24

Area of semi circle with AB as diameter

= pie r^2/2

= 3.14× 9/2 = 14.13

Area of semi circle with AC as diameter

= 3.14 × 16/2 = 3.14 × 8 = 25.12


AREA of semi circle with BC as diameter

BC= √6^2 + 8^2 = √36 +64 = 10

So 3.14 × 25/2 = 39.25

Area of semi circle with AB and AC as diameter = 14.13 +25.12 = 39.25

Now as semi circle with BC as diameter includes triangle ABC also

So 39.25 +39.25 - 24

54.5